(X^2+12)^1/2=4

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Solution for (X^2+12)^1/2=4 equation: 


X in (-oo:+oo)

((X^2+12)^1)/2 = 4 // - 4

((X^2+12)^1)/2-4 = 0

(X^2+12)/2-4 = 0

(X^2+12)/2+(-4*2)/2 = 0

X^2-4*2+12 = 0

X^2+4 = 0

(X^2+4)/2 = 0

(X^2+4)/2 = 0 // * 2

X^2+4 = 0

1*X^2 = -4 // : 1

X^2 = -4

X belongs to the empty set

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